SV#5: Unit J Concept 3-4: Solving Three-Variable Systems With Gaussian Elimination

                                                                                                                                                                                One thing that you should look for is knowing which Rows to use when your solving for a 0. For the first 0 you can use Row 1 or 2, and when it the second 0 you must use Row 1. On the last zero you also must use Row 2.

Fibonacci Beauty Ratio Activity

Name: Jesus
Foot to Navel: 109 cm  Navel to top of head: 59 cm  Ratio: 1.847
Navel to chin: 43 cm   Chin to top of head: 22 cm    Ratio: 1.955
Knee to navel: 57 cm   Foot to knee: 52 cm               Ratio: 1.09
Average: 1.631

Name: Sammy
Foot to Navel: 100 cm  Navel to top of head: 68 cm  Ratio: 1.471
Navel to chin: 49 cm    Chin to top of head: 24 cm    Ratio: 2.042
Knee to navel: 50 cm   Foot to knee: 48 cm               Ratio: 1.142
Average: 1.518

Name: Vivian
Foot to Navel: 104 cm  Navel to top of head: 68 cm  Ratio: 1.529
Navel to chin: 47 cm    Chin to top of head: 21 cm    Ratio: 2.238
Knee to navel: 58 cm   Foot to knee: 50 cm               Ratio: 1.16
Average: 1.642

Name: Christine
Foot to Navel: 98 cm    Navel to top of head: 59 cm  Ratio: 1.661
Navel to chin: 38 cm    Chin to top of head: 21 cm    Ratio: 1.809
Knee to navel: 50 cm   Foot to knee: 48 cm               Ratio: 1.042
Average: 1.504

The Golden Ratio is a number that is found using the numbers in the Fibonacci series. It is used to determine mathematical beauty by analyzing proportions. The person closest to the Golden Ratio of 1.618 was Jesus, who had an average of 1.631.
In my opinion, the Beauty Ratio is potentially useful for mathematical purposesand i had no idea how successful or accurate it was too! definitely learning some new things

SV#3: Unit H Concept 7: Finding Logs Given Approximations.

Well one thing you should look out for in this problem is knowing that there is a free clue. Some problem problems might not even use them but mine does. Also when it's already in exponential form, the Logs that have exponents, their exponents should be moved to the front of the LOG so it can be the leading coefficient.

SV#4: Unit I Concept2: Graphing Logarithmic Functions

One thing your going to want to look out for in my equation and probably most equations like this, is that when you plug it in the equation, use the change of base formula. It will make things easier and get the most accurate graph. If you change to the table you can also find key points.

SP#6: Unit K Concept 10: Repeating decimal as a rational number

First, write the decimals in a pattern, like the one that I did below the original problem. Ignore the 2 until the end. We get our "a" sub "1" by the first decimal which is 96/100, and our ratio is 1/100. Using summation notation and the geometric infinite formula we can start plugging in. The summation notation will also use the geometric sequence formula and you already have the ratio and the"a" sub "1". Next will be the infinite geometric series and just plug in (96/100) / 1-(1/100). You subtract the 1 to 1/100 and get 99/100. With (96/100) / (99/100), use the reciprocal of 99/100 and multiply it to the numerator and denominator. Now you should have 96/99, and this is were you include the 2 from the beginning. Add 2 to 96/99 and your answer will be 294/99 but reduced will be 98/33.

Well in my opinion for this problem your need to pay attention to the reciprocal part. It can be confusing and it's easy to make a mistake here. Also the part when you add 2 to 96/99 because you have to reduce and it can get tricky if you do it wrong.

WPP # 10: Unit L Concept 9-14 - Probability

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WPP # 9 : Unit L Concepts 4-8-FCP, Combinations, and Permutations

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WPP #6: Unit I Concept 3-5- Compound Interest

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WPP #4: Unit E Concept 3 - Maximizing Area

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WPP #1 Unit A Concept 6 Linear Models

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WPP#3: Unit E Concept 2 - Footballs Path

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